is_copy_assignable.hpp

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// SPDX-License-Identifier: BSL-1.0
// SPDX-FileCopyrightText: Copyright (C) 2019 Tobias Hienzsch
 
#ifndef TETL_TYPE_TRAITS_IS_COPY_ASSIGNABLE_HPP
#define TETL_TYPE_TRAITS_IS_COPY_ASSIGNABLE_HPP
 
#include <etl/_type_traits/add_lvalue_reference.hpp>
#include <etl/_type_traits/bool_constant.hpp>
#include <etl/_type_traits/is_assignable.hpp>
 
namespace etl {
 
/// \brief If T is not a referenceable type (i.e., possibly cv-qualified void or
/// a function type with a cv-qualifier-seq or a ref-qualifier), provides a
/// member constant value equal to false. Otherwise, provides a member constant
/// value equal to etl::is_assignable<T&, T const&>::value.
///
/// \details T shall be a complete type, (possibly cv-qualified) void, or an
/// array of unknown bound. Otherwise, the behavior is undefined. If an
/// instantiation of a template above depends, directly or indirectly, on an
/// incomplete type, and that instantiation could yield a different result if
/// that type were hypothetically completed, the behavior is undefined. The
/// behavior of a program that adds specializations for any of the templates
/// described on this page is undefined.
template <typename T>
struct is_copy_assignable : is_assignable<add_lvalue_reference_t<T>, add_lvalue_reference_t<T const>> { };
 
template <typename T>
inline constexpr bool is_copy_assignable_v = is_copy_assignable<T>::value;
 
} // namespace etl
 
#endif // TETL_TYPE_TRAITS_IS_COPY_ASSIGNABLE_HPP