If the expression etl::declval<T>() = etl::declval<U>() is well-formed in unevaluated context, provides the member constant value equal true. Otherwise, value is false. Access checks are performed as if from a context unrelated to either type. More...

#include <is_trivially_assignable.hpp>

Inheritance diagram for is_trivially_assignable< T, U >:

Additional Inherited Members
Public Types inherited from integral_constant< Type, Val >
using	type = integral_constant< Type, Val >

using	value_type = Type

Public Member Functions inherited from integral_constant< Type, Val >
constexpr	operator value_type () const noexcept

constexpr auto	operator() () const noexcept -> value_type

Static Public Attributes inherited from integral_constant< Type, Val >
static constexpr Type	value = Val

Detailed Description

template<typename T, typename U>
struct etl::is_trivially_assignable< T, U >

If the expression etl::declval<T>() = etl::declval<U>() is well-formed in unevaluated context, provides the member constant value equal true. Otherwise, value is false. Access checks are performed as if from a context unrelated to either type.

The documentation for this struct was generated from the following file:

include/etl/_type_traits/is_trivially_assignable.hpp

Additional Inherited Members

Detailed Description